2 results.
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Question in Bill's workspace
Using Jsxgraph to draw the vector field for a differential equation of the form dydx=f(x,y)=sin(x−y), and also by moving the point (x0,y0) you can see the solution curves going through that point.
If you want to modify f(x,y) simply change the definition of f(x,y) and that of the variable str in the user defined function testfield in Extensions and scripts. You have to use javascript notation for functions and powers in the definition of f(x,y).
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Question in Bill's workspace
Using Jsxgraph to draw the vector field for a differential equation of the form dydx=f(x,y)=x2−y2, and also by moving the point (x0,y0) you can see the solution curves going through that point.
If you want to modify f(x,y) simply change the definition of f(x,y) and that of the variable str in the user defined function testfield in Extensions and scripts. You have to use javascript notation for functions and powers in the definition of f(x,y).