Stanislav Duris
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Stanislav's activity
Stanislav Duris copied Square and cube numbers to Always, sometimes or never: square and cube numbers 8 years, 5 months ago
Stanislav Duris on Calculate powers of ten 8 years, 5 months ago
Gave some feedback: Needs to be tested
Stanislav Duris on Discrete and continuous data 8 years, 5 months ago
Gave some feedback: Needs to be tested
Stanislav Duris copied Square and cube numbers to Calculate powers of ten 8 years, 5 months ago
Stanislav Duris created Discrete and continuous data 8 years, 5 months ago
Stanislav Duris on Find bounds for distance and time spent running, given imprecise measurements 8 years, 5 months ago
Gave some feedback: Needs to be tested
Stanislav Duris on Simple interest 8 years, 5 months ago
Gave some feedback: Needs to be tested
Stanislav Duris on Dividing a polynomial with remainders, using the remainder theorem 8 years, 5 months ago
Gave some feedback: Has some problems
Stanislav Duris commented on Dividing a polynomial with remainders, using the remainder theorem 8 years, 5 months ago
You may find the code I used for this useful:
\[ \begin{align} x &=\displaystyle \frac{b}{a} \\&= \frac{\var{-k}}{\var{a}} \\&= \simplify{-({k}/{a})} \end{align}\]
Stanislav Duris commented on Dividing a polynomial with remainders, using the remainder theorem 8 years, 5 months ago
This is a short and simple straightforward question so there is not much to change.
One thing you could do to improve the advice and explain the method a bit better - describe steps of calculating "we substitute $x=\displaystyle\simplify{-({k}/{a})}$ into.." so the student doesn't get confused where the final number -b/a comes from. Maybe even display it on its own line, so it would be something like:
"....we substitute
\[ \begin{align} x &=\displaystyle \frac{b}{a} \\&= \frac{\var{-k}}{\var{a}} \\&= \simplify{-({k}/{a})} \end{align}\]
into.....".