Transition to university

Elliott Fletcher on Finding unknown coefficients of a polynomial, using the remainder theorem 8 years, 5 months ago

Gave some feedback: Needs to be tested

Lauren Richards on Dividing a polynomial with remainders, using algebraic division 8 years, 5 months ago

Gave some feedback: Has some problems

Lauren Richards commented on Dividing a polynomial with remainders, using algebraic division 8 years, 5 months ago

• I think the advice for the division should be reformulated, and focused more on being the algebraic long division with some narration. I think there should be a long division illustration of each bit of narration after it is said, and then you end up with the full one at the end. I also think the narration could be a little clearer in places. You have mentioned that you are dividing the first term of the polynomial by x, but haven't explicitly stated that that is because the first term of the divisor is x. Someone might be misled to think that dividing by x is always the first step to do, which it is not. 
• The question is quite short, would you maybe think about adding a second part where the divisor is a quadratic or something to make it a little harder?
• Would you want to include a statement? You could state what a polynomial is, or give a definition of algebraic long division or something.
• Good grammar, I can't pick you up on anything to do with that, well done haha!! 

Christian Lawson-Perfect on Using Surds, Rationalising the Denominator 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Using Surds, Rationalising the Denominator 8 years, 5 months ago

Saved a checkpoint:

I changed the denominators for parts f,g and h from number entry to mathematical expression. While the answer is always a number, a student who's misunderstood might want to write a surd. You should let them fail!

I don't know why each line of the derivations ended with a comma, but this isn't conventional.

With those things fixed, this is a good question.

Lauren Richards on Arithmetic sequences in an ice cream shop 8 years, 5 months ago

Gave some feedback: Has some problems

Lauren Richards commented on Arithmetic sequences in an ice cream shop 8 years, 5 months ago

• Typo in part b) - it says sequeces instead of sequences. Also, I think you should separate the different questions in part a) and part b) by i) and ii). 
• i) in part c) should be in italics and the writing for the question should be on the line underneath it. I would say the sentences coming after the i) should be capitalised, too. You're missing full stops at the end of the sentences in part c). 
• Is part c)ii) necessary? I'm not sure that it is particularly clear and don't think it is testing anything of importance. 
• The sequence I got given in part d) was exactly the same as the sequence I got in part c). Is it randomised? Is there a way of making sure you don't get the same sequence? I think I would put part d) as an extension of part c) and get rid of c)ii). 
• part e) - not sure that I would say "cycles through" - I think "alternates between sequentially" might be better. 
• For part c) in the advice, you have said "We can use the formula to find the 6 term." but in the parts you have managed to formulate it so it says "6th term". Also, maybe at the end of c)ii) advice, reiterate that the answer you get is the value of the 6th term. 
• I would definitely make part d)i) to be another section of part c) if the sequence is supposed to be the same. 
• I don't think the middle section of the advice for part e) is particularly clear. In the question, I actually don't think I would tell them how many flavours there are, I thinl that should be part of the question. 
• There is a typo in the advice for part e) - it says "are" instead of "our". 
• I think part a) and b) should be swapped around. For a) they need to know how to calculate the common difference and then use that to generate values but in b) they only need to calculate common differences, which is less difficult. 
• I do really like this question, and particularly part e). 

Christian Lawson-Perfect on Equations of parallel lines 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Equations of parallel lines 8 years, 5 months ago

Saved a checkpoint:

I've fixed a lot of typos, but otherwise this looks good!

Christian Lawson-Perfect on Division of fractions 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Division of fractions 8 years, 5 months ago

Saved a checkpoint:

Looks good!

Christian Lawson-Perfect on Substitute values into formulas 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Substitute values into formulas 8 years, 5 months ago

Saved a checkpoint:

Part c was wrong in a few ways! Given the formula for converting from Celsius into Fahrenheit, it asked the student to convert a temperature in Celsius into Fahrenheit - the other way round. It looks like your definition of the variable T_F was also wrong.

I've fixed those, and the rest of the question looks good.

Christian Lawson-Perfect on Equations of straight lines MCQ 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Equations of straight lines MCQ 8 years, 5 months ago

Saved a checkpoint:

I fixed a typo, but otherwise this looks good!

Christian Lawson-Perfect on Mathematical formulae - Volume 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Mathematical formulae - Volume 8 years, 5 months ago

Saved a checkpoint:

Looks OK.

Christian Lawson-Perfect on Surds simplification 8 years, 5 months ago

Gave some feedback: Ready to use

Christian Lawson-Perfect on Surds simplification 8 years, 5 months ago

Saved a checkpoint:

I'd like a description of how you decide if a root is a surd or not, like "$\sqrt{a}$ is a surd because there is no whole number $b$ such that $b^2 = a$".

Similarly for part b), describe the strategy: find a square number which divides $a$, and rewrite as $\sqrt{b^2} \times \sqrt{c}$. (Or, do what I did and multiply out the $a\sqrt{b}$ forms - much easier!)

Otherwise, this looks good.